4x^2-(1/9)y2

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Solution for 4x^2-(1/9)y2 equation: 


x in (-oo:+oo)

4*x^2-((1/9)*y^2) = 0

4*x^2+(-1/9)*y^2 = 0

4*x^2 = -(-1/9*y^2) // : 4

x^2 = 1/36*y^2

x^2 = 1/36*y^2 // ^ 1/2

abs(x) = 1/6*y

x = 1/6*y or x = -(1/6*y)

x in { 1/6*y, -(1/6*y) }

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